LET Reviewer (Material 7) - LET EXAM - Questions & Answers

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LET Reviewer (Material 7)



MATHEMATICS
Direction: Observe how the exercises in the following problems are solved. Then try to see if you can get the formula called for.

Problem 1)   Find how many pieces of cartolina can be bought for P17.00 at the rate of 2 for P4.25?
a.       8
b.      15
c.       16
d.      75
Solution: P17.00 ÷ P4.25 = 4 x 2 = 8


Problem 2)   In a company with 270 employees, out of every 9 are required to work each Sunday. How many employees are required to work Sunday?
a.       135
b.      60
c.       3
d.      18
Solution: 270 ÷ 9 = 30 No of 9’s
                30 x 2 = 60

Problem 3)   Mrs. Salve made a down payment on a lot and had a balance of P7, 200. She pays for this over a period of 2 years by making equal payments every other month. How much is the monthly installment?
a.       P600
b.      P300
c.       P36
d.      P3
e.      None of these
Solution: 24 months ÷ 2 = 12
                P7, 200 ÷ 12 = P600

Problem 4)   Mr. Ejercita borrowed P200 at 6% per annum for one (1) month in order to pay a bill of P200 on which he was allowed a discount of 2 ½ %. The net result of these two transactions was:
a.       a gain of P4
b.      a gain of P5
c.       a gain of P8
d.      a loss of P7
e.      none of these
Solution: P200 x .06 = P12
                  P12 ÷ 12 = P1 interest for 1 month
                  P 200 x 2 ½ % = P5
                  P200 – P1 = P199 borrowed
                  P200 – P1 = 195 amount par
                                                P  4   gained


Problem 5)   A staff of Basic and Co. of 20 clerks can finish a certain job in 6 days. How many more clerks should be put on the job in order to complete it in 4 working days?
a.       7
b.      13
c.       27
d.      30
e.      None of these

Solution: Let x = No. of men to finish in 4 days
                  20 : x =  4 : 6
                                4x = 120
                                  X = 30 men to finish in 4 days
                  30 – 20 = 10 men to be added


Problem 6)   A Nacida-registered factory employs 40 men at P18.00 a day, and half as many women, each at half as much pay per day. If half of the women were given the factory have to pay in a 5 – day week?
a.       P300
b.      P400
c.       P500
d.      P600
e.      None of these
Solution:  40 men at P18.00 per day    = P750.00
                   20 women at P9.00 per day =   180.00
                                                                                P930.00
                                                                                x    5  days
                                                                                P4,650.00
                  40 men at P18.00 per day    = P750.00
                  10 women at P9.00 / day     =     90.00
                  10 women at P16.00 / day  =     160.00
                                                                                P1,000.00
                                                                                X             5
                                                                                P5,000.00
                  P5,000.00
                  -4, 650.00
                P     350.00 additional amount to be paid in 5 days


Problem 7)   A wallet contains an equal of ten, twenty, and fifty-centavos coins, and the total value of the coins in the bag is P14.40. All the coins of the greatest value are worth how much more than the value of the other coins?
a.       P3.60
b.      P4.20
c.       P5.40
d.      P9.00
e.      None of these


Solution: Let x = No. of coins of each denomination
                                10x + 20x + 50x = 1,440
                                                      80x = 1,440
                                                                X = 18 no. of coins of each demonstration
                                P.10 x 18 = P1.80
                                  .20 x 18 =   3.60
                                  .50 x 18 =   9.00
                                                      P14.40

                                1.80                        P9.00 value of all coins of greatest value
                                +3.60                     -5.40 value of all other coins
                                                                P3.60 amount more than other coins


Problem 8)   A poster twice as long as it is high is fastened to a wall by 36 thumb tacks placed at 3-inches equal intervals on centers along its perimeter. How long is the poster?
a.       17.5
b.      18
c.       36
d.      35
e.      None of these
Solution:              Let x = the width
                                     2x = the length
                                       P = 2(1 + w)

                36           x              3 = 108 inches
                  2 (x    +   2x)         = 108
                  2x   +    4x             = 108
                                6x               = 108
                                 X                = 18 inches (width)
                                2x               = 36 inches (length)

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